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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy
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Application +4 | -1
Given, z=f(x)+ig(x)z=f(x)+i g(x), where i=−1i=\sqrt{-1} and f,g:(0,1)→(0,1)f, g:(0,1) \rightarrow(0,1) are real-valued functions, which of the following hold good?
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Correct option: B
z=11+ix+i(11−ix)z=\frac{1}{1+i x}+i\left(\frac{1}{1-i x}\right)
Option B (z=11+ix+i(11−ix)z=\frac{{1}}{{1+i x}}+i(\frac{{1}}{{1-i x}})) is correct because it satisfies the condition that f(x)f(x) and g(x)g(x) are real-valued functions in the range (0,1) for x∈(0,1)x \in (0,1).

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