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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1
∫xtan⁡−1x(1+x2)3/2dx=\int \frac{x \tan ^{-1} x}{\left(1+x^2\right)^{3 / 2}} d x=
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Correct option: B
x−tan⁡−1x1+x2+c\frac{x-\tan ^{-1} x}{\sqrt{1+x^2}}+c
Option C (tan⁡−1x−x1+x2+c\frac{\tan ^{-1} x-x}{\sqrt{1+x^2}}+c) is correct because substituting x=tan⁡θx = \tan \theta simplifies the integral, and integration by parts yields the correct result.

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