If $\omega \left( { \ne 1} \right)$ is a cube root of unity and ${\left( {1 + \omega } \right)^7} = A + B\omega ,\;{\rm{then}}\;A\;{\rm{and}}\;B$ are respectively

JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

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Application +4 | -1

\omega \left( { \ne 1} \right)

is a cube root of unity and

{\left( {1 + \omega } \right)^7} = A + B\omega ,\;\mathrm{then}\;A\;\mathrm{and}\;B

are respectively

View answer and explanation

Correct option: B

1,1

Option B (

1,1

) is correct because by using the property

1 + \omega = -\omega^2

and simplifying, we find that

A = 1

and

B = 1

Practice All Chapter MCQs →

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