The equilibrium, ${{\rm{P}}_4}\left( s \right) + 6{\rm{C}}{{\rm{l}}_2}\left( {\rm{g}} \right)\;\leftrightharpoons\;4{\rm{PC}}{{\rm{l}}_3}\left( {\rm{g}} \right)$ attained by mixing equal moles of ${{\rm{P}}_4}$ and ${\rm{C}}{{\rm{l}}_2}$ in a evacuated vessel. Then, at equilibrium,

$\left[ {{{\rm{P}}_4}} \right] > \left[ {{\rm{C}}{{\rm{l}}_2}} \right]$

$\left[ {{\rm{C}}{{\rm{l}}_2}} \right] > \left[ {{\rm{PC}}{{\rm{l}}_3}} \right]$

$\left[ {{\rm{C}}{{\rm{l}}_2}} \right] > \left[ {{{\rm{P}}_4}} \right]$

$\left[ {{\rm{PC}}{{\rm{l}}_3}} \right] > \left[ {{{\rm{P}}_4}} \right]$

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NEET UG CHEMISTRY MCQ: Equilibrium

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The equilibrium,

{\mathrm{P}_4}\left( s \right) + 6\mathrm{C}{\mathrm{l}_2}\left( \mathrm{g} \right)\;\leftrightharpoons\;4\mathrm{PC}{\mathrm{l}_3}\left( \mathrm{g} \right)

attained by mixing equal moles of

{\mathrm{P}_4}

and

\mathrm{C}{\mathrm{l}_2}

in a evacuated vessel. Then, at equilibrium,

View answer and explanation

Correct option: C

\left[ {{\mathrm{P}_4}} \right] > \left[ {\mathrm{C}{\mathrm{l}_2}} \right]

Option C ([P₄] > [Cl₂]) is correct because according to the stoichiometry of the reaction, 6 moles of Cl₂ react with 1 mole of P₄. Since equal moles were initially mixed, Cl₂ will be consumed to a greater extent.

NEET UG CHEMISTRY MCQ: Equilibrium

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