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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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In a Δ  ABC\Delta \;ABC, if the sides are a=3,b=5a = 3,b = 5 and c=4c = 4, then sin⁡B2+cos⁡B2\sin \frac{B}{2} + \cos \frac{B}{2} is equal to
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Correct option: A
2\sqrt 2
Option A (2\sqrt{2}) is correct because, given the sides a=3,b=5,c=4a = 3, b = 5, c = 4, angle B is 90 degrees, and sin⁡B2+cos⁡B2=2\sin \frac{B}{2} + \cos \frac{B}{2} = \sqrt{2}.

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