JEE PHYSICS MCQ: THERMODYNAMICS

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Application +4 | -1

In a thermodynamic process, helium gas obeys the law

\frac{{T}}{{P}^{2 / 5}}=

constant. The heat given to the gas when temperature of 2 moles of gas is raised from

T

2 T

View answer and explanation

Correct option: D

Zero

Option D (Zero) is correct because the process described is adiabatic, meaning no heat is exchanged with the surroundings.

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