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NEET UG CHEMISTRY MCQ: SOLUTIONS

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The degree of dissociation (α)(\alpha ) of a weak electrolyte , AxBy{A_x}{B_y} is related to van’t Hoff factor (i) by the expression
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Correct option: A
α=i−1(x+y−1)\alpha = \frac{{i - 1}}{{\left( {x + y - 1} \right)}}
Option A is correct because it correctly relates the degree of dissociation to the van't Hoff factor for a weak electrolyte.

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