JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

f:R \to R,

defined by

f\left( x \right) = {x^2} + 1,

then the values of

{f^{ - 1}}\left( {17} \right)\;and\;{f^{ - 1}}\left( { - 3} \right)

respectively are

View answer and explanation

Correct option: C

\left\{ {4, - 4} \right\},\mathrm{\;}\phi

Option C (

\{\4, -4\}, \phi

) is correct because when x=17, the inverse function yields 4 and -4, but when x=-3, the inverse function has no real solution.

More Questions from FUNCTIONS

Practice All Chapter MCQs →

f:(-\infty, 2] \longrightarrow(-\infty, 4]

f(x)=x(4-x)

f^{-1}(x)

g(f(x))=|\sin x|

f(g(x))=(\sin \sqrt{x})^2

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}