The rotors velocity of a helicopter engine changes from $300 \,\mathrm{rev} / \mathrm{min}$ to $110 \,\mathrm{rev} / \mathrm{min}$ in 2 minutes. How long does the rotor blades take to stop

JEE PHYSICS MCQ: SYSTEM OF PARTICLES

1 Hard

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Application +4 | -1

The rotors velocity of a helicopter engine changes from

300 \,\mathrm{rev} / \mathrm{min}

110 \,\mathrm{rev} / \mathrm{min}

in 2 minutes. How long does the rotor blades take to stop

View answer and explanation

Correct option: A

3 min

Option A (3 min) is correct because it is calculated by first finding the angular acceleration and then the time it takes for the rotor to stop.

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\mathrm{AB}

\mathrm{L}

\mu(x)=a+\frac{b x}{L}

x

\mathrm{A}

\mathrm{CM}

\left(\frac{7}{12}\right) \mathrm{L}

\mathrm{A}

\mathrm{b}

1.0 \mathrm{~g}

8 \mathrm{~cm}

\omega = {t^4} + 2{t^3}

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)