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JEE PHYSICS MCQ: MECHANICAL PROPERTIES OF FLUIDS

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The work done in blowing a soap bubble of surface tension 0.06Nm−10.06 \mathrm{Nm}^{-1} from 2 cm2 \mathrm{~cm} radius to 5 cm5 \mathrm{~cm} radius is
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Correct option: B
0.003168 J0.003168 \mathrm{~J}
Option B (0.003168 J0.003168 \mathrm{~J}) is correct because it is the work done calculated using the formula for the increase in surface area of a soap bubble.

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