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JEE PHYSICS MCQ: OSCILLATIONS

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Application +4 | -1

The potential energy of a particle of mass

1 \mathrm{~kg}

in motion along the

x

-axis is given by

U=4(1-\cos 2 x) \mathrm{J}

, where

x

is in metres. The period of small oscillations (in second) is

View answer and explanation

Correct option: C

\frac{\pi}{2}

Option C (

\frac{\pi}{2}

) is correct because the period of small oscillations is calculated using the second derivative of the potential energy.

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