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JEE MATHEMATICS MCQ: FUNCTIONS

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Domain of the function f(x)=x2−3x+2x2+x−6f(x)=\frac{x^{2}-3 x+2}{x^{2}+x-6} is
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Correct option: D
{x:x∈R,x≠2,x≠−3}\{x: x \in R, x \neq 2, x \neq-3\}
Option D (x:x∈R,x≠2,x≠−3\\{x: x \in R, x \neq 2, x \neq-3\\}) is correct because the denominator cannot be zero, so x2+x−6≠0x^2 + x - 6 \neq 0, which means (x−2)(x+3)≠0(x-2)(x+3) \neq 0, so x≠2x \neq 2 and x≠−3x \neq -3.

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