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JEE PHYSICS MCQ: GRAVITATION

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Two particles of masses mm and MM are initially at rest at infinite distance. Find their relative velocity of approach due to gravitational attraction when dd is their separation at any instant.
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Correct option: A
2G(M+m)d\sqrt{\frac{2 G(M+m)}{d}}
Option A (2G(M+m)d\sqrt{\frac{2 G(M+m)}{d}}) is correct because it is derived from the conservation of energy, considering the reduced mass and gravitational potential energy.

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