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JEE MATHEMATICS MCQ: TANGENTS & NORMALS

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Application +4 | -1
If the tangent to the curve y=f(x)=xlog⁡ex,(x>0)y = f\left( x \right) = x{\log _e}x,\left( {x > 0} \right) at a point (c,f(c))\left( {c,f\left( c \right)} \right) is parallel to the line segment joining to the points(1,0) and (e, e) then c=
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Correct option: B
e(1e−1){e^{\left( {\frac{1}{{e - 1}}} \right)}}
Option B (e^(1/(e-1))) is correct because the derivative of the function at point c must equal the slope of the line segment joining the two points, which can be solved for c.

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