JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

\frac{{z - \alpha }}{{z + \alpha }}\left( {\alpha \in R} \right)

is a purely imaginary number and

\left| z \right| = 2,

then a value of

\alpha

View answer and explanation

Correct option: D

Option D (2) is correct because when (z - alpha)/(z + alpha) is purely imaginary and |z| = 2, solving for alpha gives alpha = 2.

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