$\smallint \,\,\left( {1 + x - {x^{ - 1}}} \right){e^{x + {x^{ - 1}}}}\,\,dx$ is equal to

$\left( {x + 1} \right)\,\,{e^{x + {x^{ - 1}}}}\,\, + \,\,c$

$\left( {x - 1} \right)\,\,{e^{x + {x^{ - 1}}}}\,\, + \,\,c$

JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

1 of 1

Analyzing +4 | -1

\int \,\,\left( {1 + x - {x^{ - 1}}} \right){e^{x + {x^{ - 1}}}}\,\,dx

is equal to

View answer and explanation

Correct option: D

x{e^{x + {x^{ - 1}}}}\,\, + \,\,c

Option D (

x{e^{x + {x^{ - 1}}}}\, + \,c

) is correct because by using integration by parts, the integral simplifies to this expression.