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JEE CHEMISTRY MCQ: P-BLOCK ELEMENTS

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Analyzing +4 | -1
Assertion (A) : XeF6\mathrm{XeF}_6 can be used as an oxidising agent.

Reason (R) : Oxidation state of Xee\mathrm{Xe}_{\mathrm{e}} in XeF6\mathrm{XeF}_6 is +6{+ 6}.
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Correct option: B
Both A\mathbf{A} and R\mathbf{R} are true but R\mathbf{R} is not the correct explanation of A\mathbf{A}.
The correct answer is B (Both A and R are true but R is not the correct explanation of A) because XeF6 can act as an oxidizing agent due to the high electronegativity of fluorine, but the +6 oxidation state of Xe is not the direct reason for its oxidizing ability.

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