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JEE PHYSICS MCQ: OSCILLATIONS

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A simple harmonic motion is represented by

x(t)=\sin ^2 \omega t-2 \cos ^2 \omega t

. The angular frequency of oscillation is given by

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Correct option: B

2 \omega

Option B (

2 \omega

) is correct because the given expression can be simplified to a cosine function with angular frequency

2 \omega

.

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Assertion: A particle executing simple harmonic motion comes to rest at the extreme positions.

Reason: The resultant force on the particle is zero at these positions. A particle is subjected simultaneously to two SHM’s one along the

x

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y

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a

. When the PE of a particle is one-fourth of its maximum value during the oscillation, its displacement from the equilibrium position will be The displacement, velocity and acceleration in a simple harmonic motion are related as the Assertion: Angular velocity of earth around sun is lesser than the angular velocity of moon about earth.
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SHM

. At a displacement

{y_1}

its potential energy is

{U_1}

and at a displacement

{y_2}

its potential energy is

{U_2}

. The potential energy of the particle at displacement

\left( {{y_1} + {y_2}} \right)