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JEE PHYSICS MCQ: OSCILLATIONS

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Analyzing +4 | -1
Two pendulums of length 1 m and 16 m start vibrating one behind the other from the same stand. At some instant, the two are in the mean position in the same phase. The time period of shorter pendulum is T. the minimum time after which the two threads of the pendulum will be one behind the other is?
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Correct option: C
4T/34T/3
Option C (4T/3) is correct. It is derived by finding the time when the two pendulums are in phase again, considering their different time periods.

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