JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Easy

1 of 1

Analyzing +4 | -1

Any tangent to the curve

y = 2{x^5} + 4{x^3} + 7x + 9

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Correct option: C

Makes an acute angle with the

x

-axis

Option A (Parallel) is correct because the tangents at the points where the curve crosses the x-axis have the same slope.

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a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z