JEE MATHEMATICS MCQ: MEAN VALUES THEOREM

1 Easy

1 of 1

Application +4 | -1

Let

f(x)=3 x^4-4 x^2+5

. Then a value of

c

in Lagrange's mean value theorem for

f(x)

on the interval

[-1,1]

View answer and explanation

Correct option: C

\sqrt{\frac{2}{3}}

Option C (

\sqrt{\frac{2}{3}}

) is correct because it is a value within the interval

[-1, 1]

that satisfies Lagrange's Mean Value Theorem for the given function.

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\int\limits_3^5 {f\left( x \right)} \,dx

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f\left( x \right) = x\left( {x - 1} \right)\left( {x - 2} \right)