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JEE MATHEMATICS MCQ: MEAN VALUES THEOREM

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The value of cc in Lagrange's theorem for the function f(x)=∣x∣f(x)=|x| in the interval [−1,1],[-1,1], is
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Correct option: D
Non-existent in the interval
Option D (Non-existent in the interval) is correct because f(x)=∣x∣f(x) = |x| is not differentiable at x=0x=0 in the interval (−1,1)(-1, 1), and Lagrange's theorem requires differentiability on the open interval.

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