The value of \( \cos 255^{\circ}+\sin 195^{\circ} \) is

\( \frac{\sqrt{3}-1}{2 \sqrt{2}} \)

JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy

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Application +4 | -1

The value of

\cos 255^{\circ}+\sin 195^{\circ}

View answer and explanation

Correct option: C

-\left(\frac{\sqrt{3}-1}{\sqrt{2}}\right)

Option C (-(

\frac{\sqrt{3}-1}{\sqrt{2}}

)) is correct because it is the simplified value of the given trigonometric expression.

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\triangle A B C

C

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\sin ^2(A / 2)+\sin ^2(B / 2)-\sin ^2(C / 2)=