JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

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Application +4 | -1

\omega

is an imaginary cube root of unity then the value of

\sin \left(\left(\omega^{19}+\omega^{101}\right) \pi-\frac{\pi}{6}\right)

View answer and explanation

Correct option: C

\frac{1}{2}

Option C (

\frac{{1}}{{2}}

) is correct because after simplifying the expression using properties of cube roots of unity, the sine of the resulting angle is 1/2.

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