JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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\int e^x\left(\frac{1}{x}-\frac{1}{x^2}\right) d x=

View answer and explanation

Correct option: C

\frac{e^x}{x}+c

Option C (

\frac{{e^x}}{{x}}+c

) is correct because the integral is of the form

\int e^x [f(x) + f'(x)] dx = e^x f(x) + c

, where

f(x) = \frac{{1}}{{x}}

and

f'(x) = -\frac{{1}}{{x^2}}

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