The angle between curves $y^2=4 x$ and $x^2+y^2=5$ at $(1,2)$ is

JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Medium

1 of 1

Application +4 | -1

The angle between curves

y^2=4 x

and

x^2+y^2=5

(1,2)

View answer and explanation

Correct option: A

\tan ^{-1}(3)

Option A (

\tan^{-1}(3)

) is correct because by finding the derivatives of both curves at the point (1,2) and using the formula for the angle between two lines, we can find the angle between the curves.

More Questions from TANGENTS & NORMALS

Practice All Chapter MCQs →

The complete set of value of '

a

' for which there exists at least one line that is tangent to the graph of the curve

y=x^3-a x

at one point and normal to the graph at another point is given by The point of intersection of the tangents drawn to the curve

x^2 y=1-y

at the points where it is met by the curve

x y=1-y

, is given by Let

C

be the curve

y^3-3 x y+2=0

. If

H

is the set of points on the curve

\mathrm{C}

where the tangent is parallel to

x

-axis and

V

is the set of points on

C

where the tangent is parallel to

y

-axis, then The curve

y-e^{x y}+x=0

has a vertical tangent at the point: If normal to the curve

y = f\left( x \right)

is parallel to

x

-axis, then The tangents to the curve

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

at the points

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z

are parallel to: