JEE MATHEMATICS MCQ: TANGENTS & NORMALS

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Application +4 | -1

The tangent line at

(-1,15)

to the curve

y=2 x^{3}+13 x^{2}+5 x+9

passes through

View answer and explanation

Correct option: A

Origin

Option A (Origin) is correct because the equation of the tangent line at (-1, 15) is y + 15x = 0, which passes through the origin (0,0).

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a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z