JEE MATHEMATICS MCQ: STRAIGHT LINES

1 Easy

1 of 1

Analyzing +4 | -1

a \ne b \ne c,

then the equations

\left( {b - c} \right)x + \left( {c - a} \right)y + \left( {a - b} \right) = 0

and,

\left( {{b^3} - {c^3}} \right)x + \left( {{c^3} - {a^3}} \right)y + \left( {{a^3} - {b^3}} \right) = 0

will represent the same line, if

View answer and explanation

Correct option: D

a + b + c = 0

Option D (

a + b + c = 0

) is correct because it's the condition that makes the two given equations represent the same line.

More Questions from STRAIGHT LINES

Practice All Chapter MCQs →

x-3 y=p, a x+2 y=q

a x+y=r

\left\{ {a{t_1}{t_2},\;a\left( {{t_1} + {t_2})\} ,\{ a{t_2}{t_3},a({t_2} + {t_3}} \right)} \right\},\;\left\{ {a{t_3}{t_1},\;a\left( {{t_3} + {t_1}} \right)} \right\}

y = 2\;x + 4

6x = 3y + 5

{x^2} + {y^2} + 2xy - 8ax - 8ay - 9{a^2} = 0

(3,8)

x+3 y=7

\left( {{x^2} + 7xy + 2{y^2}} \right)\left( {y - 1} \right) = 0