A hypothetical reaction $A \rightarrow 2 B$ proceeds through the following sequence of steps. I $A \rightarrow C ; \Delta_r H=q_1$ II $C \rightarrow D ; \Delta_r H=q_2$ III $\frac{1}{2} D \rightarrow B ; \Delta_r H=q_3$ The heat of hypothetical reaction is

NEET UG CHEMISTRY MCQ: THERMODYNAMICS

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Analyzing +4 | -1

A hypothetical reaction

A \rightarrow 2 B

proceeds through the following sequence of steps.

I

A \rightarrow C ; \Delta_r H=q_1

C \rightarrow D ; \Delta_r H=q_2

III

\frac{1}{2} D \rightarrow B ; \Delta_r H=q_3

The heat of hypothetical reaction is

View answer and explanation

Correct option: B

q_1+q_2+2 q_3

Option B (

q_1+q_2+2 q_3

) is correct because the overall heat of reaction is the sum of the heats of each step, considering the stoichiometry.

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{T_i}

{T_f}

\mathrm{H}_2 \mathrm{O}(\mathrm{s}) \rightarrow \mathrm{H}_2 \mathrm{O}(\mathrm{g})

\mathrm{X}_2 \mathrm{O_4(l}) \longrightarrow 2 \mathrm{XO}_2(\mathrm{g}), \Delta U=2.1 \mathrm{~kcal}, \Delta S=20 \mathrm{~cal} \mathrm{~K}^{-1}

300 \mathrm{~K}

\Delta G