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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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Application +4 | -1
If in a △ABC,∠B=90∘\triangle A B C, \angle B=90^{\circ}, then tan⁡2(A2)\tan ^2\left(\frac{A}{2}\right) is equal to
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Correct option: A
b−cb+c\frac{b-c}{b+c}
Option A (b−cb+c\frac{b-c}{b+c}) is correct because it is derived by using the definition of cosine and the half-angle formula for tangent in a right-angled triangle.

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