JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

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Analyzing +4 | -1

a,b

are two fixed positive integers such that

f\left( {a + x} \right) = b + {\left[ {{b^3} + 1 - 3{b^2}f\left( x \right) + 3b\;{{\left\{ {f\left( x \right)} \right\}}^2} - {{\left\{ {f\left( x \right)} \right\}}^3}} \right]^{1/3}}

For all

x \in R,

then

f\left( x \right)

is a periodic function with period

View answer and explanation

Correct option: B

2a

The correct answer is B (2a) because by substituting f(a+x) into the original equation twice, we find that f(x+2a) = f(x), indicating a period of 2a.

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