JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1

The value of the function

f\left( x \right) = 3\sin \left( {\sqrt {\frac{{{\pi ^2}}}{{16}} - {x^2}} } \right)

lies in the interval

View answer and explanation

Correct option: B

\left[ {0,\;3/\sqrt 2 } \right]

Option B ([0, 3/√(2)]) is correct because it represents the range of the function, considering the domain restriction and the sine function's properties.

More Questions from FUNCTIONS

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f:(-\infty, 2] \longrightarrow(-\infty, 4]

, where

f(x)=x(4-x)

, then

f^{-1}(x)

is given by: If

g(f(x))=|\sin x|

and

f(g(x))=(\sin \sqrt{x})^2

, then Let

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

be defined by

f\left( x \right) = x - \left[ x \right]

, then

{f^{ - 1}}\left( x \right)

equals Let

f: R \rightarrow R

be defined as

f(x)=x^4

, Choose the correct answer. Which of the following functions are odd functions Let

f(x)=(x+1)^2-1(x \geq-1)

. Then the set

S=\left\{x: f(x)=f^{-1}(x)\right\}

contains