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JEE MATHEMATICS MCQ: FUNCTIONS

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Analyzing +4 | -1
If f:R→Rf:R \to R is defined by f(x)=x−[x]−12  for  x∈Rf\left( x \right) = x - \left[ x \right] - \frac{1}{2}\;for\;x \in R, where [x]\left[ x \right] is the greatest integer not exceeding xx, then

{x∈R:f(x)=12}\left\{ {x \in R:f\left( x \right) = \frac{1}{2}} \right\} is equal to
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Correct option: C
ϕ\phi, the empty set
Option C (ϕ\phi, the empty set) is correct because the equation f(x)=12f(x) = \frac{1}{2} leads to a contradiction, meaning there are no real solutions.

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