Skip to main content
Back to ELECTRO CHEMISTRY

NEET UG CHEMISTRY MCQ: ELECTRO CHEMISTRY

1 Easy
1 of 1
Application +4 | -1
Molar conductivities (Λm∘{\mathop \mathrm{\Lambda }\limits^ \circ _m}) at infinite dilution of NaCl,HCl\mathrm{NaCl},\mathrm{HCl} and CH3COONa\mathrm{C}{\mathrm{H}_3}\mathrm{COONa} are 126.4, 425.9 and 91.0 Scm2mol−1{\rm{S {\kern 1pt} {\kern 1pt}c}}{\mathrm{m}^2}{\kern 1pt} \mathrm{mo}{\mathrm{l}^{ - 1}} respectively.Λm∘{\mathop \mathrm{\Lambda }\limits^ \circ _m} for CH3COOH\mathrm{C}{\mathrm{H}_3}\mathrm{COOH} will be :
View answer and explanation
Correct option: D
390.5 Scm2mol−1{\rm{S {\kern 1pt} {\kern 1pt}c}}{\mathrm{m}^2}{\kern 1pt} \mathrm{mo}{\mathrm{l}^{ - 1}}
Option D is correct because, according to Kohlrausch's law, the molar conductivity of CH3COOH at infinite dilution is the sum of the molar conductivities of CH3COONa and HCl, minus the molar conductivity of NaCl, resulting in 390.5 S cm² mol⁻¹.

More Questions from ELECTRO CHEMISTRY

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.