Two identical cylinders $A$ and $B$ with frictionless pistons contain the same ideal gas at the same temperature and the same volume $V$. The mass of gas $A$ is $m_A$ and that of $B$ is $m_{B}$. The gas in each cylinder is now allowed to expand isothermally to the same final volume $2 {V}$. The change in the pressure in ${A}$ and $B$ are found to be $\Delta P$ and $2 \Delta P$ respectively. Then,

JEE PHYSICS MCQ: THERMODYNAMICS

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Analyzing +4 | -1

Two identical cylinders

A

and

B

with frictionless pistons contain the same ideal gas at the same temperature and the same volume

V

. The mass of gas

A

m_A

and that of

B

m_{B}

. The gas in each cylinder is now allowed to expand isothermally to the same final volume

2 {V}

. The change in the pressure in

{A}

and

B

are found to be

\Delta P

and

2 \Delta P

respectively. Then,

View answer and explanation

Correct option: C

2 m_A=m_B

Option C (

2 m_A=m_B

) is correct because it is derived from the isothermal expansion and pressure change relationships for ideal gases.