JEE MATHEMATICS MCQ: STRAIGHT LINES

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Analyzing +4 | -1

If the quadrilateral formed by the lines

a x+b y+c=0, a^{\prime} x+b^{\prime} y+c=0, a x+b y+c^{\prime}=0

a^{\prime} x+b^{\prime} y+c^{\prime}=0

have perpendicular diagonals, then

View answer and explanation

Correct option: C

{a^2} + {b^2} = {a'^2} + {b'^2}

Option C (

{a^2} + {b^2} = {a'^2} + {b'^2}

) is correct because the quadrilateral is a rhombus, implying equal distances between parallel sides.

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y = 2\;x + 4

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\left( {{x^2} + 7xy + 2{y^2}} \right)\left( {y - 1} \right) = 0