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JEE CHEMISTRY MCQ: S-BLOCK ELEMENTS

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Analyzing +4 | -1
Na2SO3\mathrm{N}{\mathrm{a}_2}\mathrm{S}{\mathrm{O}_3} and NaHCO3\mathrm{NaHC}{\mathrm{O}_3} may be distinguished by treating their aqueous solution with:
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Correct option: D
MgSO4\mathrm{MgS}{\mathrm{O}_4}
Option D (MgSO4\mathrm{MgS}{\mathrm{O}_4}) is correct because Na2CO3Na_2CO_3 reacts with MgSO4MgSO_4 to form a precipitate of magnesium carbonate, while NaHCO3NaHCO_3 does not.

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