JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy

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Application +4 | -1

\cos \,\,x + {\cos ^2}x = 1

, then the value of

{\sin ^{12}}x + 3\,\,{\sin ^{10}}x + 3\,\,{\sin ^8}x + {\sin ^6}x - 1

, is equal to

View answer and explanation

Correct option: D

\mathrm{0}

Option D (0) is correct because the expression simplifies to 0 after substituting cos x = sin²x.

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