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JEE PHYSICS MCQ: OSCILLATIONS

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Application +4 | -1
A simple wave motion is represented by y=5(sin⁡ 4 π t+3cos⁡ 4 π t)y=5(\sin \,4 \,\pi\, t+\sqrt{3} \cos \,4 \,\pi \,t). Its amplitude is
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Correct option: D
10 units
Option D (10 units) is correct because the amplitude is found by converting the equation into the form Asin⁡(ωt+ϕ)A \sin(\omega t + \phi) and calculating A.

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