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JEE PHYSICS MCQ: OSCILLATIONS

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The velocity vector vv and displacement vector xx of a particle executing SHM are related as vdvdx=−ω2x\frac{v d v}{d x}=-\omega^2 x with the initial condition v=v0v=v_0 at x=0x=0. The velocity vv when displacement is xx, is
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Correct option: B
v=v02−ω2x2v=\sqrt{v_0^2-\omega^2 x^2}
Option B (v=v02−ω2x2v=\sqrt{v_0^2-\omega^2 x^2}) is correct because it is the result of integrating the given differential equation with the specified initial condition.

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