JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

1 Easy

1 of 1

Application +4 | -1

y(t)

is a solution of

(1+t) \frac{d y}{d t}-t y=1

and

y(0)=-1

, then

y(1)

is equal to

View answer and explanation

Correct option: A

-\frac{1}{2}

Option A (-

\frac{{1}}{{2}}

) is correct because, after solving the differential equation and applying the initial condition, y(1) equals -

\frac{{1}}{{2}}

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