If $f: R \rightarrow R$ is given by $f(x)=3 x-5$, then $f^{-1}(x)$ ?

Does not exist because $f$ is not one-one

Does not exist because $f$ is not onto

JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1

f: R \rightarrow R

is given by

f(x)=3 x-5

, then

f^{-1}(x)

View answer and explanation

Correct option: B

Is given by

\frac{x+5}{3}

Option B (

\frac{{x+5}}{{3}}

) is correct because it represents the inverse function obtained by swapping

x

and

y

and solving for

y

Practice All Chapter MCQs →

f:(-\infty, 2] \longrightarrow(-\infty, 4]

f(x)=x(4-x)

f^{-1}(x)

g(f(x))=|\sin x|

f(g(x))=(\sin \sqrt{x})^2

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}