NEET UG CHEMISTRY MCQ: 13 TH GROUP ELEMENTS (P-BLOCK)

1 Hard

1 of 1

Analyzing +4 | -1

Assertion (A) : In aqueous solution

{AlCl}_3

forms dimer

{Al}_2 {Cl}_6

.
Reason (R) : The high enthalpy of hydration is sufficient to break the covalent dimer into

\left[M\left({H}_2 {O}\right)_6\right]^{3+}

and

{Cl}^{-}

ions.

View answer and explanation

Correct option: D

\mathbf{A}

is false but

\mathbf{R}

is true.

Option D (

\mathbf{A}

is false but

\mathbf{R}

is true) is correct because

AlCl_3

does not form a dimer in aqueous solution; it forms hydrated ions, and the high enthalpy of hydration is indeed sufficient to break any potential covalent dimer.

More Questions from 13 TH GROUP ELEMENTS (P-BLOCK)

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The hardest compound of boron is: Which does not show inert pair effect? Which one of the following does not exist in the free state On strong heating of

{H}_3 {PO}_4

and

{H}_3 {BO}_3

, sum of oxidation number of

{P}\, \& {~B}

in the final product obtained is Compound ‘X’ reacts with

N{H_3}

to 473 K give another compound ‘Y’. X can be prepared by heating

B{F_3}

with sodium hydride. The compound ‘Y’ is represented by the formula Assertion: Electronegativity first increases from B to Al and then decreases from Al to

\mathrm{TI}

.

Reason: Due to poor shielding by inner

\mathrm{d}

and

\mathrm{f}

electrons.