$\smallint \,\,\frac{{d\,(\cos \,\,{\rm{\theta }})}}{{\sqrt {1\,\, - \,\,{{\cos }^2}\,{\rm{\theta }}} }}$ is equal to

${\sin ^{ - 1}}\,\,(\cos \,\,{\rm{\theta }})\,\, + \,\,c$

${\cos ^{ - 1}}\,\,{\rm{\theta }}\,\, + \,\,c$

${\sin ^{ - 1}}\,\,{\rm{\theta }}\,\, + \,\,c$

JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Understanding +4 | -1

\int \,\,\frac{{d\,(\cos \,\,\mathrm{\theta })}}{{\sqrt {1\,\, - \,\,{{\cos }^2}\,\mathrm{\theta }} }}

is equal to

View answer and explanation

Correct option: D

{\sin ^{ - 1}}\,\,(\cos \,\,\mathrm{\theta })\,\, + \,\,c

Option D (

{\sin ^{ - 1}}\,(\cos \,\mathrm{\theta })\, + \,c

) is correct because the integral can be directly computed using the definition of arcsin.