JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Application +4 | -1

z=\cos \theta+i \sin \theta

, then

\frac{z^{2 n}-1}{z^{2 n}+1}

, where

n

is an integer, is equal to

View answer and explanation

Correct option: B

i \tan n \theta

Option B (

i \tan n \theta

) is correct because after applying De Moivre's theorem and trigonometric identities, the expression simplifies to

i \tan n \theta

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