JEE CHEMISTRY MCQ: SOLID STATE

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Silver metal crystallises in a cubic closed packing arrangement with the edge of the unit cell

{a}=407\, \mathrm{pm}

. The radius of silver atom is

(X+3.9) \mathrm{pm}

. Find the value of

X

View answer and explanation

Correct option: A

140

The correct answer is A (140) because the radius of the silver atom is calculated using the face-centered cubic (fcc) relationship between the edge length and the radius.

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