The temperature gradient in the earth’s crust is 32$^ \circ C$ k${{\rm{m}}^{ - 1}}$ and the mean conductivity of earth is 0.008 cal${{\rm{s}}^{ - 1}}{\rm{c}}{{\rm{m}}^{ - 1}}^ \circ {C^{ - 1}}$. Considering earth to be a sphere of radius 6000 km loss of heat by earth everyday is about

JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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The temperature gradient in the earth’s crust is 32

^ \circ C

{\mathrm{m}^{ - 1}}

and the mean conductivity of earth is 0.008 cal

{\mathrm{s}^{ - 1}}\mathrm{c}{\mathrm{m}^{ - 1}}^ \circ {C^{ - 1}}

. Considering earth to be a sphere of radius 6000 km loss of heat by earth everyday is about

View answer and explanation

Correct option: D

{10^{18}}

cal

Option D (

{10^{18}}

cal) is correct because it is calculated using the formula for heat loss considering the temperature gradient, conductivity, and earth's surface area.

JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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