JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

Let

\mathrm{f}(\mathrm{x})=[x]

, where

[x]

denotes the greatest integer less than or equal to

x

. If

a=\sqrt{2011^{2}+2012}

, then the value of

\mathrm{f}(\mathrm{a})

is equal to

View answer and explanation

Correct option: B

2011

Option B (2011) is correct because the greatest integer less than or equal to

a = \sqrt{2011^2 + 2012}

is 2011.

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