In the electrochemical reaction, $2{\rm{F}}{{\rm{e}}^{3 + }} + {\rm{Zn}} \to {\rm{Z}}{{\rm{n}}^{2 + }} + 2{\rm{F}}{{\rm{e}}^{2 + }}$ increasing the concentration of ${\rm{F}}{{\rm{e}}^{2 + }}$

NEET UG CHEMISTRY MCQ: ELECTRO CHEMISTRY

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Understanding +4 | -1

In the electrochemical reaction,

2\mathrm{F}{\mathrm{e}^{3 + }} + \mathrm{Zn} \to \mathrm{Z}{\mathrm{n}^{2 + }} + 2\mathrm{F}{\mathrm{e}^{2 + }}

increasing the concentration of

\mathrm{F}{\mathrm{e}^{2 + }}

View answer and explanation

Correct option: C

Decreases the cell emf

Option C is correct. According to the Nernst equation, increasing the concentration of the product (Fe²⁺) will decrease the cell emf.

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