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JEE MATHEMATICS MCQ: FUNCTIONS

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Analyzing +4 | -1
The set of all real xx satisfying the inequality 3−∣x∣4−∣x∣>0\frac{{3 - \left| x \right|}}{{4 - \left| x \right|}} > 0
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Correct option: A
[−3,  3]∪(−∞,  −4)∪(4,  ∞)\left[ { - 3,\;3} \right] \cup \left( { - \infty ,\; - 4} \right) \cup \left( {4,\;\infty } \right)
The correct answer is A. By analyzing the inequality and considering the cases where the numerator and denominator have the same sign, we find the solution set to be (-∞, -4) U [-3, 3] U (4, ∞).

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